2010 Challenger Banque Nationale de Rimouski – gra podwójna

Debel
2010 Challenger Banque Nationale de Rimouski
Finał
Mistrzowie Australia
Australia Kaden Hensel Adam Hubble
Wicemistrzowie United States
United States Scotta Lipsky'ego Davida Martina
Wynik 7–6(5), 3–6, [11–9]
Wydarzenia
Syngiel Debel
← 2008 · Challenger de Rimouski   · 2011

Kaden Hensel i Adam Hubble wygrali w finale 7-6(5), 3-6, [11-9], pokonując Scotta Lipsky'ego i Davida Martina .

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Pierwsza runda Ćwierćfinały Półfinały Egzaminy końcowe
1 South Africa
Netherlands R de Voest R Wassen
6 4 [10]
  Canada
Canada PL Duclos P Polansky
4 6 [7] 1 South Africa
Netherlands R de Voest R Wassen
6 6  
  Canada
Canada V Pospisil M. Raonic
bez       Spain
Australia A Brugues-Davi N Roshan
4 3  
  Spain
Australia Brugues-Davi Nima Roshan
      1 South Africa
Netherlands R de Voest R Wassen
6 5 [7]
3 Australia
Australia K Hensel A Hubble
6 6   3 Australia
Australia K Hensel A Hubble
4 7 [10]
toaleta Canada
Canada P Bester Kamil Pajkowski
2 2   3 Australia
Australia K Hensel A Hubble
4 6 [10]
  United States
United States B Evans Kuzniecow
6 7     United States
United States B Evans Kuzniecow
6 2 [7]
  Romania
Portugal C Gârd L Tavares
3 5   3 Australia
Australia K Hensel A Hubble
7 3 [11]
  Montenegro
Sweden D Danilović M. Ryderstedt
4 6 [6] 2 United States
United States S Lipsky D Martin
6 5 6 [9]
ALT South Africa
Montenegro A Anderson G Tošić
6 3 [10] ALT South Africa
Montenegro A Anderson G Tošić
6 1 [10]
ALT Australia
Australia B Klein J. Millman
2 6 [9] 4 India
Austria P Amritraj M Slanar
2 6 [8]
4 India
Austria P Amritraj M Slanar
6 4 [11] ALT South Africa
Montenegro A Anderson G Tošić
3 6 5  
  United States
United States Bogomołow Jr. N Monroe
      2 United States
United States S Lipsky D Martin
6 7  
  Australia
Australia N Lindahl M. Matosevic
bez       United States
United States Bogomołow Jr. N Monroe
5 4  
toaleta Israel
Canada Weintrauba Zachary'ego White'a
4 6 [5] 2 United States
United States S Lipsky D Martin
7 6  
2 United States
United States S Lipsky D Martin
6 2 [10]